Shi Ting Ong
Asked 9 years ago

SG chevron_right Primary 6 chevron_right Number and Algebra

Can help please! P6 question

Replies 2

Soo Vei Li

We know that the goldfish is $10 and the average of the two fish is $7. So, we can ask (10+?)/2 = 7 and work out that the angelfish costs $4.. Or we can say that since average of $7, the total cost is $7*2 = $14, the angelfish is $4. Knowing then that the goldfish costs $6 more than the angelfish, we can find out how many goldfish was bought.

6 years ago
Soo Vei Li

One of the concepts about average is that the average*number of objects = total quantity.

6 years ago

Ariel Lim Ah Ping
Asked 9 years ago

SG chevron_right Primary 6 chevron_right Fractions

Replies 5

Caleb Tey

6 years ago
Ariel Lim Ah Ping

Thanx, Caleb!

6 years ago
Caleb Tey

My boxes a bit messy. Start with the green then the brown lines are step 2.

6 years ago
Ariel Lim Ah Ping

Can understand. Thanx. Not messy

6 years ago
Arlene Tan

Thank you!

6 years ago

Ariel Lim Ah Ping
Asked 9 years ago

SG chevron_right Primary 6 chevron_right Number and Algebra

Replies 16

Yeo See Yeong

Total sweets difference between giving 7 sweets and 6 sweets is 11 sweets. Hence, there are 11 children. Since there is a surplus of 2 sweets if 6 were given, so 11*6+2= 68

6 years ago
Jacqueline Teo Mei Hui

6 years ago
Ariel Lim Ah Ping

Thanx, Yeo n Jacqueline.

6 years ago
Ariel Lim Ah Ping

Arlene Tan

6 years ago
Izam Marwasi

Alternative approach..

6 years ago
Yeo See Yeong

Another way.

6 years ago
Ariel Lim Ah Ping

Izam Marwasi, don't really understand your method

6 years ago
Jon Liow PM

Hope my attempt to solve this qn helps.

6 years ago
Soo Vei Li

Here's something visual to help students understand the thinking regarding the number of children. For students working on this problem for the first time, it would be good for them to work with counters, chips, etc to 'act it out'. The abstract thinking and calculations can follow after that.

6 years ago
Xin Yi Ng

Is this p4 question?

6 years ago
Arlene Tan

P6!

6 years ago
Jacqueline Teo Mei Hui

P4 topics factors n multiples

6 years ago
Ariel Lim Ah Ping

Adrian Ng, see vei li soo's model

6 years ago
Wen Kiat Koo

Here is an alternative to working out the answer without using guess and check

6 years ago
Ariel Lim Ah Ping

thanx, wen kiat. algebra I know too. was looking for non-algebra methods.

6 years ago
Caroline Lim

Using multiples of 7 & 6

6 years ago

Tan Weiqiang
Asked 9 years ago

SG chevron_right Primary 5 chevron_right Fractions

Today's question does not require the use of models. Instead, it requires students to recognise that a common shaded area for 2 different objects that overlap can be represented with different values. Essentially, the values are the same and students have to make them the same in order to be able to solve the question. Hope it helps!

Replies 0

Ng Siewkhim
Asked 9 years ago

SG chevron_right Primary 3 chevron_right Number and Algebra

Pls help with the working, tks!

Replies 8

Chong Ji Lian

6 years ago
Ng Siewkhim

Thanks!

6 years ago
Kheng Leong Fong

27 ÷3 = 9 sets 9 sets of (3+8) = 99

6 years ago
Rakhi Vinisha Samtani

99

6 years ago
Rakhi Vinisha Samtani

Cause for each set of 8 he gets 3 free: with 27 free that's 9 sets, so 9x8 + 27 = 99

6 years ago
Eva Ong

27➗3=9 9X8=72 72 + 27 =99

6 years ago
Nurul Sakinah

99

6 years ago
Jacqulin Joseph

6 years ago