Vivian Ang
Asked 9 years ago

SG chevron_right Primary 6 chevron_right Number and Algebra

Help please!Thanks😀

Replies 0

KrishnaVane Thiruganasambanthan
Asked 9 years ago

SG chevron_right Primary 5 chevron_right Number and Algebra

Replies 7
Zhong Shu Hao

lol tbis one requires units and parts.... i think...

6 years ago
KrishnaVane Thiruganasambanthan

more tougher than i thought

6 years ago
Zhong Shu Hao

Unshaded area ratio of B:C = 10:1 Full area rato of B:C = 2:1 We want to change this full ratio to a new ratio, say p:q, such that p-10 = q-1

6 years ago
Zhong Shu Hao

2:1 = 4:2 = 6:3 = ... = 18:9

6 years ago
Zhong Shu Hao

Hence, Full ratio = 18:9 Unshaded ratio = 10:1 Shaded area = 8 units 8 units --> 104cm^2 1 unit --> 13 cm^2 Area of B = 18 units. Area of A = 21 units Area of A that is not covered by B = 3 units = 3 x 13cm^2 = 39cm^2.

6 years ago
KrishnaVane Thiruganasambanthan

Zhong Shu Hao: thanks once again

6 years ago
Zhong Shu Hao

Welcome!

6 years ago

KrishnaVane Thiruganasambanthan
Asked 9 years ago

SG chevron_right Primary 5 chevron_right Number and Algebra

Guys pls hell me with these two sums... i did not know ratio can be this tough... is there a trick

Replies 0

KrishnaVane Thiruganasambanthan
Asked 9 years ago

SG chevron_right Primary 5 chevron_right Number and Algebra

Replies 12
Zhong Shu Hao

Starting with this....

6 years ago
Zhong Shu Hao

Finding area of C. note that the shaded square is also a part of square C!

6 years ago
Zhong Shu Hao

And finally.... Area of A

6 years ago
Zhong Shu Hao

Now.... find the total sum of non shaded area.

6 years ago
KrishnaVane Thiruganasambanthan

Zhong Shu Hao: hi for finding C ... how u did you total units as 8 ... could u explain pls

6 years ago
Zhong Shu Hao

because ratio of B:C is 5:4. Since area of B is 10u, area of C will 8u.

6 years ago
KrishnaVane Thiruganasambanthan

oh i get it now ... okay thanks

6 years ago
Zhong Shu Hao

btw... area of A can be found more simply by just multiplying the area of B by 2.

6 years ago
KrishnaVane Thiruganasambanthan

yes that is what i did

6 years ago
KrishnaVane Thiruganasambanthan

thanks alot

6 years ago
Zhong Shu Hao

Q 2 is the same approach

6 years ago
KrishnaVane Thiruganasambanthan

Zhong Shu Hao: sorry q2 where do i start with

6 years ago

Karen Tan
Asked 9 years ago

SG chevron_right Primary 6 chevron_right Number and Algebra

Sorry to trouble u all.. need help

Replies 0

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