Xin Yi Ng
Asked 9 years ago

SG chevron_right Primary 3 chevron_right Measurement

P3

Replies 3

Ida Tan

6 years ago
Yeo See Yeong

6 years ago
Shuping Hao

1-1/8 - (1/8 + 1/4)=1/2

6 years ago

Neelam Mirji
Asked 9 years ago

SG chevron_right Primary 5 chevron_right Number and Algebra

P5 sum. Please help

Replies 2

Yeo See Yeong

He is in 108 position. Think this question shd say there are at most x number of ppl in the queue. Else it is possible to have other answers.

6 years ago
Neelam Mirji

Well . Thanks Mr. Yeo

6 years ago

Geeta Sudarshan
Asked 9 years ago

SG chevron_right Primary 5 chevron_right Number and Algebra

2] Chetan and his 5 siblings buy a present for their mother on Mother's Day. As the eldest brother, he pays 0.2 of the cost of the present. The rest of his siblings share the balance equally. Each sibling pay dollar 9.50 less that Chetan. What is the cost of the present?

Replies 5

Yeo See Yeong

Remaining 5 siblings paid for 80%, hence each of the 5 paid 16%. 20%-16% = 4% = $9.50. Hence 100% = $9.50 × 100 ÷ 4 = $237.50

6 years ago
Geeta Sudarshan

tks

6 years ago
Adrian Ng

https://www.facebook.com/photo.php?fbid=10153080947219353&set=gm.483418851814776&type=1&theater

6 years ago
Joey Kty

Hi, This is for P5?

6 years ago
Geeta Sudarshan

yes

6 years ago

Geeta Sudarshan
Asked 9 years ago

SG chevron_right Primary 5 chevron_right Number and Algebra

p5 math problem.. pl help with a solution :1] 0.55 of a box of chocolates are dark chocolate, 0.3 are milk chocolate and the rest are white chocolate. There are 138 pieces more dark chocolate than white chocolate. How many pieces of chocolate are there in the box?

Replies 2

Yeo See Yeong

15% is white chocolate. Since 40% (55%-15%) = 138, hence 100% = 138×100÷40 = 345

6 years ago
Yap Michelle

6 years ago

Serene Koon
Asked 9 years ago

SG chevron_right Primary 6 chevron_right Number and Algebra

Pls help Pri 6 math

Replies 10

Roses Myna

The question is how many red pens must be move from stall B to stall A SO THAT 50% OF THE PENS IN STALL A ARE RED. Stall A has 40 red pens and 45 blue pens. How many more red pens you need in stall A so that its became equal = 50 % per color?

6 years ago
Cheekoon Ng

I hate these kinds of questions... I always ask, why do you even want to move the pens?

6 years ago
Serene Khoo

Follow

6 years ago
Yap Michelle

Hope I am right and helps.

6 years ago
Shuping Hao

40+x=(40+45+x)*50% 80+2x=85+x So, x=5

6 years ago
Serene Koon

Thanks Michelle Yap n Shuping HaoHow.

6 years ago
Shuping Hao

6 years ago
Shuping Hao

Welcome!~

6 years ago
Jojo Celestino

This is actually kind of overwhelming after you read it for the first time but if you are familiar with the different heuristics, this is actually a very simple problem. If you want the number of red pens in stall A to be 50% in the end that means the number of red and blue pens in stall A in the end must be the same. Since you are only transferring red pens from stall B to stall A that means that the number of blue pens in stall A before and after the transfer should be the same. If in the end, there are 45 blue pens in stall A, (since only red pens were transferred) then this means that there are also 45 red pens in stall A in the end. (50% are red, 50% are blue). If at first there were 40 red pens and in the end there are 45, then this tells us that 5 red pens were transferred. Hope this helps.. :)

6 years ago
Serene Koon

Thanks Jojo CelestinoCelestial. Your detailed explanation definitely help

6 years ago