And correct. Thank you so much

Thanks a lot!😄😃

32= 2 x 2 x 2 x 2 x 2 48= 2 x 2 x 2 x 2 x 3 From here, we can see that the dimensions of V is 4 x 8, while the dimensions of W is 6 x 8. Dimensions of X = (4+6) x (4+6) = 10 x 10. Hence, Area of X = 10m x 10m = 100m^2

Total length of wire (going from top left corner of X, in clockwise order) = 10m + 8m + 4m + 6m + 8m + 10m + 10m = 56m.

Shu Hao, is my working correct?

yup

Thank you!

Another possible configuration is U: 2 by 16 V: 3 by 16 This means X: 5 by 5 = 25cm^2 Such questions usually has a disclaimer clause "the following diagram isn't drawn to scale" So in solving, we may need to provide all possibilities.

U?

W ☺

V & W ☺

Can we just find the sides based on areas given?

Like Raymond Ng has mentioned, there are 2 sets of possibilities.

Not saying that Raymond Ng's working is wrong, but i prefer my ans as my dimensions "LOOKS" more to scale... lol

Like I mentioned, I've seen several schools over the years who, based on the "disclaimer clause", penalise students solutions. I've witnessed such situations from top schools eg RI/RGS/HCI/DHS/ACSI to neighbourhood schools. So as a tutor, I usually advocate providing all possibilities as viable solutions, not merely one of the solutions.

ANS: 24:6:85

I got the same answer as the previous answer posted (but got deleted). How to get the 85?

Girls 8u, boys 9u. 9u-8u=1u. 1u =100. Total pupils 17u=1700.

Oops wrong entry. Should be 425😁