Just to clarify, is there a mistake in the question -- is the amount that May has left $1400 instead of $1700?

Could be. Cos when my husband tried to solve it using algebra method, he didn't get a whole number as answer. If it is $1400, how would you solve it using model or other method?

Thanks!

B's slower speed of 2km/h caused B to be behind A by 1/5 of the route after 4h. Hence, 1/5 of route = 4h x 2km/h = 8km Length of route = 8km x 5 = 40km/h

Zhong Shu Hao last step 8×5

Oh ps

Thx Tan Junhong Corrected now :)

7am --> 10am 3h has passed. Distance travelled by P= 3h x 60km/h = 180km Distance travelled by Q= 300km - 180km = 120km Speed of Q= 120km/3h = 40km/h .

Rate of first tap: 1/4 tank/h Rate of second tap: 1/3 tank/h Amount filled in 1 hour = 1/4 + 1/3 = 7/12 tank Rate of third tap = -1/2 tank/h Net rate of water flowing out = 1/4 - 1/2 = -1/4 tank/h Time taken for tank to be empty= (7/12) / (1/4) h = 7/3 h = 2h 20min.

But the answer is 4 hours

Lemme check through

OK. Thank you

Q2 not Q1 right? 😅

Sorry! I thought that your solution is for the first question! Your answer is correct! Thanks a lot!😄😃

Lol okay 😉

U need help for first Q?

Can you help me with the first question too! Thanks again!😄

Ya...thanks

Rate of first pipe=1/6 pool/h Rate of second pipe= 1/8 pool/h Total volume of water in pool after two hours= 2x (1/6 + 1/8) = 7/12 pool full. Rate of third pipe= -1/12 pool/h Net rate of water filling up= 1/8 + 1/6 - 1/12 = 5/24 pool/h Volume of pool not yet filled = 5/12 pool Time taken= (5/12) / (5/24) h = 2h Total time taken= 2h + 2h = 4h.

Thanks soooooooooooo much! 😄😃😊

Welcome ☺️