Find the are of the circle segments PQ, QR, and RP. Ans should be 12pi - 15. So the area of the "lip" POQ and POR is 24pi-30 each.
Now add an arc to QR, such that the arc passes through point O. You realise u get another identical lip, QOR.
Area of all 3 lips=
3 x (24pi - 30)=
72pi - 90
This value exceeds the area of the circle by 36pi - 90. This is the area of 3 of such shaded parts. So area of each shaded part=
(36pi - 90)/3
=12pi - 30
Pressing calculator,
Area =7.68 cm^2