Chris Chan
Asked 9 years ago

SG chevron_right Primary 4 chevron_right Fractions

P4 question. Pls help

Replies 12

Stacey Tan

6 years ago
Yeo See Yeong

I also get 2.5 but not sure if it can be in decimal.

6 years ago
Chris Chan

I also got 2.5 but teacher says is wrong

6 years ago
BA Poh Ann

Fig 1: 1/2 x 24 = 12 1/3 x 24 = 8 12 - 8 = 4 Fig 2: 1/3 x 36 = 12 1/4 x 36 = 9 12 - 9 = 3 Fig 3: 1/2 x 20 = 10 1/4 x 20 = 5 10 - 5 = 5

6 years ago
Mark Quitco

Its 5:) although instead of getting the difference of each fraction of the number on top (1/2 of 20 is 10, 1/4 of 20 is 5) I saw that the greatest common factor of each example had the same answer as well☺

6 years ago
Lee Boon Leon

Yes it is 5

6 years ago
Mike Tan

24 x 1/2 x 1/3 = 4 36 x 1/3 x 1/4 = 3 20 x 1/2 x 1/4 = 2.5 ans = 2.5

6 years ago
Choy Ban Heng

Actually, this question is considered ambiguous. With only two complete examples in the sequence, there are many ways to interpret the pattern. Both 2.5 and 5 should be accepted because they are both reasonable answers. Unless the question specifies that the missing number is an integer or whole number, otherwise the teacher should accept the answer 2.5.

6 years ago
Kho Tek Hong

We can go by the common denominator or the two given fractions, 6, 12, and 4 respectively. 20/4=5

6 years ago
Chris Chan

Thanks all. I also think we shouldn't be faulted for answer in fraction since the question has fractions itself.

6 years ago
Randy Yap

5 .

6 years ago
Randy Yap

Just multiply the fraction to the top number and find the deference

6 years ago

Adrian Ng
Asked 9 years ago

SG chevron_right Primary 6 chevron_right Number and Algebra

Making it visual...

Replies 0

Ida Tan
Asked 9 years ago

SG chevron_right Primary 5 chevron_right Fractions

Need help with this P5 question, TIA!

Replies 4

KH Puah

6 years ago
Ida Tan

Thanks KH Puah !

6 years ago
Yeo See Yeong

6 years ago
Ida Tan

Thanks Yeo See Yeong!

6 years ago

Christelle Tay
Asked 9 years ago

SG chevron_right Primary 3 chevron_right Number and Algebra

Need help on this question for P3 Math, is there any equation for this

Replies 10

Zhong Shu Hao

suppose all are stools--> 54 legs we need 10 more legs 1 chair has 1 more leg than 1 stool chairs needed --> 10/1=10

6 years ago
Zhong Shu Hao

number of stools =18-10=8.

6 years ago
靖雯 黄

My boy's working Used the least number of legs x total items 3 x 18 = 54 After minus fr total legs 64-54 = 10 10 is for chair 18-10 = 8 stools

6 years ago
Amos N Siew Peng

6 years ago
Hwee Koon

Or can draw 18 circles first with 3 legs n assume all are stools Then start to add on additional legs to make them become chairs till there are 64 legs in all. Easier to understand for kids who are visual.

6 years ago
Catherine Wong

For P3 you should apply guess and check for this type of questions

6 years ago
Catherine Wong

8 legs = 2 chairs , 9 legs = 3 stool = 17 legs 16 legs = 4 chairs , 18 legs = 6 stools = 34 legs 36legs = 9 chairs , 21legs = 7 stools = 57 legs 40 legs = 10 chairs , 24legs = 8 stools 40+24= 64 legs Revised din saw the total 18 chairs

6 years ago
Shi Ting Ong

Assume all chairs 18x4=72 72-64=8 4-3=1 8 divide by 1=8(stools) 18-8=10(chairs)

6 years ago
Stacey Tan

Given that the child is in P3, we should use the Guess and Check. The assumption method is probably best introduce at a later age, probably P5 or P6.

6 years ago
Lydia Wade

All the chairs and stools have at least 3 legs. So because there are 18 items, then 54 legs are used up (18x3) ensuring that each item has at least 3 legs. So because you have 10 extra legs of the total of 64 legs, the 10 can only belong to chairs, with one extra leg per chair, meaning there are 10 chairs. And because you only have 18 items, the other 8 must be stools.

6 years ago

Shi Ting Ong
Asked 9 years ago

SG chevron_right Primary 6 chevron_right Number and Algebra

Help please P6 question. Thanks

Replies 7

Yeo See Yeong

Sorry, x is supposed to be delivery due date.

6 years ago
Lydia Wade

I'm not quite sure ur solution is correct cos 20088/206 is not a whole number. I maybe wrong but I'm assuming to b whole number 😓 BUT I do not have the solution now too....

6 years ago
Yeo See Yeong

Hi Lydia Wade, you are right that it is not a whole number. It would need to produce 97.51units per day to produce 20,088 laptops by the delivery date. Which is not possible. Hence it will either complete production before or after the delivery date. Maybe I am wrong.. I don't know.

6 years ago
Lydia Wade

Hi See Yeong, I have no idea too! I'm still trying to solve it! My poor old brain...

6 years ago
Lydia Wade

Hi See Yeong, ur answer is correct. My hubby explained ur models and then also solved it using simultaneous equations to arrive exactly to ur numbers. Clever people :))

6 years ago
Kim Soon Chin

See Yeong's answer is correct. Amt of laptops is 20088 and must b completed in 206 days. Note that the question only asking for days given to complete certain amount of laptops. We can imagine if we were given the task, how should we plan the production. 20088/206=97.514563. If produce 97 daily, still short of 106. Therefore out of the 206 days, 106 days need to produce 98 laptops and the rest of 100 days only need to produce 97 laptops.

6 years ago
Kim Soon Chin

6 years ago