SG chevron_right Primary 5 chevron_right Number and Algebra
X is common between the given 2 ratios. Must make them have the same number. Then and only then you can combine X, Y and Z
X:Y=2:7, multiple by 3 to give 6:21 Z:X=4:3, multiple by 2 to give 8:6 Now, Z:X:Y=8:6:21
X:Y = 2:7 = 6:21 (x3) X:Z = 3:4 = 6:8 (x2) X+Z:Y = 6+8:7 = 14:7 = 2:1.
Y should be 21
Yes, got it. Thank you all
Answer: (1)
Can we do it via algebraic method? x/y=2/7 so y=7/2x, z= 4/3x (x+z)/ y = (x+4/3 x) / (7/2 x) = (7/3 x) / (7/2 x) = 2/3 so x+z/y = 2/3 so x+z :y = 2:3
Hi, P5 Question. Thank you.
The ratio of A:C is 5:3. Try to rework on your model and you may be able to solve this problem.
Ratio of C: A+B?
The ratio A:B, multiple by 5, ie. 15:5 The ratio A:C, multiple by 3 ,ie, 15:9 This will make A have the same number, namely 15
A:B:C = 15:5:9
Yes. Got it already. Thanks. Another one coming up. Same concept but it's a big number. 😰
SG chevron_right chevron_right
thanks for adding!
SG chevron_right Primary 6 chevron_right Number and Algebra
Help please. Thanks.
what age is this?
P6 Paul Booth
Help please. Thanks
50 + 70 = 120 360 ÷ 120 = 3 3 h after 10.30 p.m., they would meet each other at 1.30 a.m.
P6.Paul Booth
thank you