I think using ratio to solve will be easier ?

Sorry, forgot to mention that this is a P4 q. Ratio not been taught yet.

Thanks Ida Tan for the detailed explanation!

Which level is this question for?

It is a p5 question

I see. Then the above working should make sense.

Thanks yueh Mei

Here's one using the table form.

Thanks Mike ! I think there is an error in your working but anyway I managed to figure it out

Yes last ratio i left out B

Thanks for ur help !

Ans:$1.20

Of course, assuming all the files cost the same and so do the notepads. 10 files and 6 notepads cost $16.50. So you can find the cost of 6 files.

5F + 3N= $8.25........A 4F + 6N =$9.30........B Common LCM ...B /2. ..... 2F + 3N $9.30 / 2 =$4.65 5F - 2F=$8.25 - $4.65 =$3.60 3F=$3.60 1F=$1.20 1 File =$1.20 Hope it's help

Yet another way: 9 files and 9 notebooks cost $17.55. 1 file and 1 notebook cost $1.95. Use this to eliminate the files (or the notebooks). The cost of a notebook is $0.75, and the cost of a file is $1.20. This problem is inappropriate for P3.

This doesn't sound like a P3 question, it sounds more like a P6 question where calculators are allowed. May I know where you get this qn from?

Hi thanks for contributions but this is my kid p3 mind stretcher questions. Don't think they teach algebra to solve this question currently.

this is simultaneous equations covered in late P5 or P6

double the 5 files and 3 notes to get 10 files and 6 notes making these things $16.50. then use this $16.50 minus the 4 files and 6 notes means the 6 files remaining costs $7.20. ($16.50 - $9.30) Thus each file is $1.20.

A pictorial approach is helpful. Draw say triangles and circles to represent files and notebooks respectively.

(5f3n $8.25) x2 = 10f6n $16.50 4f6n $9.30 ------------ Hence: 10-4f=6f and $16.50-$9.30=$7.20 :$7.20/6 = $1.20per file.

16.50-9.30=7.20. One file 1.20.

834

Thanks