Vanitha Guna
Asked 9 years ago

SG chevron_right Primary 5 chevron_right Number and Algebra

Need help.

Replies 6

Choy Ban Heng

Note that 1/100 + 99/100 = 1; 2/100 + 98/100 = 1; 3/100 + 97/100 = 1; and so on. 1. You need to "count" how many such pairs. 2. The last pair is 49/100 + 51/100, and so there are ... pairs. 3. Plus the 50/100 that is not accounted for. :)

6 years ago
Vanitha Guna

thanks

6 years ago
Beng Ti Tan

So should be 99 ?

6 years ago
Sharon Thio

1/100 to 49/100 + corresponding 99/100 to 51/100 = 49 pairs = 49. Take whole number 49 + 50/100 (0.5) = 49.5

6 years ago
Beng Ti Tan

Thanks Sharon !

6 years ago
Pieter Cronje

6 years ago

Vanitha Guna
Asked 9 years ago

SG chevron_right chevron_right

Thanks for adding me.

Replies 0

Winnie Win
Asked 9 years ago

SG chevron_right Primary 5 chevron_right Fractions

Replies 9

Jojo Celestino

Hi! I think since Tom can assemble half of a toy when Jerry can only assemble a quarter means that Tom can assemble a toy twice as fast as Jerry. So, if Tom assembled a fifth of a toy, Jerry had only assembled half of what Tom had, thus, Jerry had assembled half of a fifth which is a tenth. I hope my answer helps.. :)

6 years ago
Beng Ti Tan

Agreed w Jojo

6 years ago
Stella Cheong

Hi, can share what level this is ? Thanks

6 years ago
Sherri Chuah

Hope this helps.

6 years ago
Elaine Eo

I'd say 1/10.

6 years ago
Winnie Win

Hi, Stella Cheong! It's from P6.

6 years ago
Winnie Win

Thanks everyone for your guidance.

6 years ago
Stella Cheong

Thanks Suzzie Toh

6 years ago
Adrian Ng

6 years ago

Lee Yuet Meng
Asked 9 years ago

SG chevron_right Primary 4 chevron_right Number and Algebra

Paiseh, pls help with 1 more. TIA!

Replies 6

Darryl Seah

6 years ago
Yueh Mei Liu

6 years ago
Darryl Seah

Awesome. :-)

6 years ago
Lee Yuet Meng

Thank you!!!

6 years ago
Adrian Ng

6 years ago
Yeo See Yeong

Why am I still using algebra!!! Urghh...

6 years ago

Lee Yuet Meng
Asked 9 years ago

SG chevron_right Primary 4 chevron_right Number and Algebra

Hello, anyone around to help. Is the answer 45? How to explain? What is the method to use other than counting? TIA!

Replies 9

Michael Tan

10 teams. 1st team = 9 matches; second team play 8 matches; third team 7 matches...............10th team 0 match. Thus Total matches = 9+8+7+6+5+4+3+2+1 = 45 matches.

6 years ago
Lee Yuet Meng

I got 45 too. So it's simply by counting and adding. No models, tables or formulae?

6 years ago
Michael Tan

This is quite direct. Solve quite fast. Use simple ways to solve and save time. Don;t need model. As every team will play with other teams. But in decreasing number in order to avoid repetition. This is the way to solve i believe. Fast and simple :)

6 years ago
Michael Tan

Can draw diagram to illustrate understanding...

6 years ago
Chia-Chan Bk

6 years ago
Hong Keng Kor

Agree with all above methods. But is it not easier to consider tt there are 5 matches each round, and since each team needs to play agst 9 other teams, so total there are 9 rounds. Answer will be 5 x 9 = 45

6 years ago
Pieter Cronje

Adding 1+2+3........9 can be done with adding it AGAIN. 1+9..2+8..3+7.....giving 10x9=90. But this must be halved...giving45. Einstein used this method of adding a series...

6 years ago
Pieter Cronje

It does introduce a series. Good example. A plays 9 games...B plays 8 (its. Game with A has been added) and carry on...then introduce the einstein trick! Kids will love it!

6 years ago
Pieter Cronje

6 years ago