Given equations
3x+2y=12 -eq1
6x+3y=21-eq2
Multiply eq 1 with 2 then we get
6x+4y=24-eq3
Subtract eq3 from eq2 we get
6x+4y-(6x+3y)=24-21
Y=3.
Now keep y =3 in eq 1 we get
3x+2(3)=12
3x=12-6
X=2
D is the correct option.
You can guess the correct option by keeping x and y values in the options.
4 years ago
azzkikronu2
Asked 4 years ago
SG
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Secondary 3
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Geometry and Measurement