SG chevron_right Secondary 2 chevron_right Add Math: Calculus
Refer
SG chevron_right Primary 6 chevron_right Fractions
The figure shows a circle and two overlapping quater circles in a square of side 20cm. Find the total area of the shaded parts. Give your answer correct to 1 decimal place.
Refer to photo
SG chevron_right Grade: N/A chevron_right Strand: N/A
I don't understand
Given SN=SP=8, and JK and MI forms right angle with
the radius, it means JK= ML; so 4x-2 = 10; x=3
Correction to first statement: Given SN=SP=8, and JK and ML forms right angle with
PL=1/2 ML since radius is at right angle, which also means SML is an isoceles triangle, so PL=1/2(10)=5
SG chevron_right Primary 5 chevron_right Statistics
Pls help. Thanks
$30
If AB is perpendicular to BC, gradient of AB = -1/ gradient of BC; so gradient of AB= 6/3=2; gradient of
BC= (3-k)/(k+5-2)=(3-k)/(k+3); Substituting: 2=-(k+3)/(3-k); 2(3-k)=-k-3; 6-2k=-k-3; k=9.