SG chevron_right Secondary 3 chevron_right Statistics and Probability
Need Solution . Sorry for Picture Quality.
SG chevron_right Primary 5 chevron_right Fractions
Please help to answer the question 9 and 10
9: 3 1/2 10: 7 1/2
SG chevron_right Primary 6 chevron_right Number and Algebra
Need help. TIA
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Is it area of square 49/7=7 (in red)?
Take square root of 49 which is 7
As bxb = 49 bXb =7x7 So b=7
Is clear now
Ok understand. Thank u
Square Side : ETriangle Side 2:1 49---- what x what = 49 7 × 7 = 49 ---. ---- 7 ÷ 2 = 3.5 3.5 × 3 = 10.5 Ans: 10.5cm
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Yes, its clear. Thank u so much.
SG chevron_right Primary 6 chevron_right Fractions
Percentage
See attached image Answer is 16%